Ad Unit

Let vectors A⃗ =(1,0,−3), B⃗ =(−2,5,1), and C⃗ =(3,1,1). (2B⃗ )×(3C⃗ ) =

Let vectors A⃗ =(1,0,−3), B⃗ =(−2,5,1), and C⃗ =(3,1,1).
(2B⃗ )×(3C⃗ ) =

The answer is :

24,30,-102

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