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Let vectors A⃗ =(2,1,−4), B⃗ =(−3,0,1), and C⃗ =(−1,−1,2). 2(B⃗ ⋅3C⃗ ) =

Let vectors A⃗ =(2,1,−4), B⃗ =(−3,0,1), and C⃗ =(−1,−1,2).
2(B⃗ ⋅3C⃗ ) =

The answer is :

30

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